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Scientists have determined that when nutrients are sufficient, the number of bacteria grows exponentially. Suppose there are initially 1000 bacteria, and this number increases to 3000 after ten minutes.

a) What is the growth rate of the bacteria?

Answer :

The number of bacteria increases to 3000 after ten minutes, the Growth model suggests that the initial number of bacteria was approximately 333.33.

The number of bacteria grows exponentially when nutrients are sufficient. We are given two data points: there are 1000 bacteria initially, and after ten minutes, the number of bacteria increases to 3000.

To model the exponential growth of bacteria, we can use the general exponential growth formula:

N(t) = N₀ * e^(kt),

where:

- N(t) represents the number of bacteria at time t,

- N₀ represents the initial number of bacteria,

- e is the mathematical constant approximately equal to 2.71828,

- k is the growth rate constant, and

- t represents the time.

Using the given information, we can substitute the values into the equation:

1000 = N₀ * e^(10k), -- Equation 1

3000 = N₀ * e^(20k). -- Equation 2

Dividing Equation 2 by Equation 1, we get:

3000/1000 = e^(20k)/e^(10k).

Simplifying the equation further:

3 = e^(10k).

Taking the natural logarithm of both sides:

ln(3) = ln(e^(10k)),

ln(3) = 10k.

Now, we can solve for k by dividing both sides by 10:

k = ln(3) / 10.

Substituting the value of k back into Equation 1:

1000 = N₀ * e^(10 * ln(3) / 10),

1000 = N₀ * e^ln(3),

1000 = N₀ * 3,

N₀ = 1000 / 3.

Therefore, the initial number of bacteria is approximately 333.33.

1000 bacteria, and the number of bacteria increases to 3000 after ten minutes, the growth model suggests that the initial number of bacteria was approximately 333.33.

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