We appreciate your visit to Terrell s company sells candy in packs that are supposed to contain 50 red candies 25 orange and 25 yellow He randomly selected a pack. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To determine if the sample fails the large counts condition for the chi-square goodness-of-fit test, we'll follow these steps:
1. Understand the Expected Percentages: The candies are supposed to be distributed as 50% red, 25% orange, and 25% yellow.
2. Calculate the Expected Counts: Since the total number of candies is 16:
- Expected count for red candies: [tex]\( 16 \times 0.5 = 8 \)[/tex]
- Expected count for orange candies: [tex]\( 16 \times 0.25 = 4 \)[/tex]
- Expected count for yellow candies: [tex]\( 16 \times 0.25 = 4 \)[/tex]
3. Compare with the Observed Counts: The observed counts for each color were:
- Red: 9
- Orange: 5
- Yellow: 2
4. Check the Large Counts Condition: This condition requires that all expected counts should be at least 5 to ensure the validity of the chi-square test.
- The expected count for red candies is 8 (which is 5 or more).
- The expected count for orange candies is 4 (which is less than 5).
- The expected count for yellow candies is 4 (which is less than 5).
5. Conclusion: The expected counts for orange and yellow candies (both being 4) make this sample fail the large counts condition, because they are less than 5. Hence, the sample does not adequately meet the conditions for a chi-square goodness-of-fit test due to these smaller expected counts.
1. Understand the Expected Percentages: The candies are supposed to be distributed as 50% red, 25% orange, and 25% yellow.
2. Calculate the Expected Counts: Since the total number of candies is 16:
- Expected count for red candies: [tex]\( 16 \times 0.5 = 8 \)[/tex]
- Expected count for orange candies: [tex]\( 16 \times 0.25 = 4 \)[/tex]
- Expected count for yellow candies: [tex]\( 16 \times 0.25 = 4 \)[/tex]
3. Compare with the Observed Counts: The observed counts for each color were:
- Red: 9
- Orange: 5
- Yellow: 2
4. Check the Large Counts Condition: This condition requires that all expected counts should be at least 5 to ensure the validity of the chi-square test.
- The expected count for red candies is 8 (which is 5 or more).
- The expected count for orange candies is 4 (which is less than 5).
- The expected count for yellow candies is 4 (which is less than 5).
5. Conclusion: The expected counts for orange and yellow candies (both being 4) make this sample fail the large counts condition, because they are less than 5. Hence, the sample does not adequately meet the conditions for a chi-square goodness-of-fit test due to these smaller expected counts.
Thanks for taking the time to read Terrell s company sells candy in packs that are supposed to contain 50 red candies 25 orange and 25 yellow He randomly selected a pack. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada