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Answer :
There are 100 mEq of ammonium chloride present in a 20-mL vial.
Let's calculate step by step:
1. Calculate the total milligrams of NH₄CI in the vial:
267.5 mg/mL} × 20mL = 5350 mg
2. Convert milligrams to millimoles (mmol) by dividing by the molecular weight of NH₄CI (53.5 g/mol):
5350 mg ÷ 53.5 g/mol = 100 mmol
3. Finally, since 1 mmol of NH₄CI is equivalent to 1 mEq, the number of milliequivalents (mEq) of ammonium chloride in the vial is equal to the number of millimoles of NH₄CI present in the vial:
100 mmol = 100 mEq
Therefore, there are 100 mEq of ammonium chloride present in a 20-mL vial.
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