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Answer :
Final answer:
The number of different permutations of "examination" before the first word starting with 'm' is 1814399, given that there are 4 starting letters before 'm' and the remaining 10 letters can be permuted in 10!/(2!) ways.Therefore,the correct answer is (D)1814399 words.
Explanation:
The number of different permutations of the word "examination" can be calculated using the permutation formula considering the repeated letters. The word contains 11 letters with 'n' occurring twice. To find the permutations before the first word starting with 'm', we will consider the letters alphabetically prior to 'm', which are 'a', 'e', 'i', and 'n'. Each of these letters can take the first position, and the permutations of the rest can be calculated subsequently.
For each starting letter, the remaining 10 letters (accounting for the repeating 'n') can be permuted in 10!/(2!) ways.
Thus, the number of words before the first starting with 'm' is 4 * (10!/(2!)). This equals 4 * (3628800/2) = 1814400. However, since all words that start with 'm' are required to be excluded, the correct answer is 1814399 words.
The closest option to this number is Option C (362879), which most likely represents a typographical error, as it should be half of this value to be considered correct. Therefore, the correct number of words (with or without meaning) before the first word starting with 'm' would be 1814399, which is half the number listed in Option C.
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