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Answer :
To find the first number in the pair of consecutive numbers, let's follow these steps:
1. Start with the given equation: [tex]\(2n + 1 = 157\)[/tex].
2. The goal is to solve for [tex]\(n\)[/tex], which represents the first number. First, we need to eliminate the constant on the left side of the equation. To do this, subtract 1 from both sides of the equation:
[tex]\[
2n + 1 - 1 = 157 - 1
\][/tex]
Simplifying this gives us:
[tex]\[
2n = 156
\][/tex]
3. Now, to find [tex]\(n\)[/tex], divide both sides of the equation by 2:
[tex]\[
\frac{2n}{2} = \frac{156}{2}
\][/tex]
Simplifying this results in:
[tex]\[
n = 78
\][/tex]
Thus, the first number is 78. Therefore, the answer is B. 78.
1. Start with the given equation: [tex]\(2n + 1 = 157\)[/tex].
2. The goal is to solve for [tex]\(n\)[/tex], which represents the first number. First, we need to eliminate the constant on the left side of the equation. To do this, subtract 1 from both sides of the equation:
[tex]\[
2n + 1 - 1 = 157 - 1
\][/tex]
Simplifying this gives us:
[tex]\[
2n = 156
\][/tex]
3. Now, to find [tex]\(n\)[/tex], divide both sides of the equation by 2:
[tex]\[
\frac{2n}{2} = \frac{156}{2}
\][/tex]
Simplifying this results in:
[tex]\[
n = 78
\][/tex]
Thus, the first number is 78. Therefore, the answer is B. 78.
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