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Answer :
Final answer:
The acceleration of the sled in the horizontal direction is 0.35 m/s^2.
Explanation:
To find the acceleration of the sled in the horizontal direction, we need to resolve the pulling force into its horizontal component. The horizontal component can be calculated using the equation:
F_horizontal = F * cos(theta)
where F is the magnitude of the pulling force and theta is the angle above the horizontal. Plugging in the given values, we get:
F_horizontal = 128 N * cos(60 degrees) = 128 N * 0.5 = 64 N
Next, we need to calculate the net force in the horizontal direction. The net force is given by:
F_net = F_horizontal - frictional force = 64 N - 35 N = 29 N
Finally, we can calculate the acceleration using Newton's second law:
a = F_net / m = 29 N / 82 kg = 0.35 m/s^2
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