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Answer :
Final answer:
The equilibrium constant Kp and Kc for the reaction C₁₀H₈(s) ⇌ C₁₀H₈(g) can be calculated using the given vapor pressure of naphthalene at 27ºC. The correct answer is option D: 5.34x10⁻⁶, 1.82x10⁻⁴.The correct answer is option D: 5.34x10⁻⁶, 1.82x10⁻⁴.
Explanation:
The equilibrium expression for the reaction C₁₀H₈(s) <—> C₁₀H₈(g) is defined by the equilibrium constant Kc, which is the ratio of the concentrations of the reactant and product species at equilibrium. The equilibrium constant Kp, on the other hand, is defined as the ratio of the partial pressures of the gaseous reactant and product species. In this question, we are given the vapor pressure of naphthalene at a specific temperature. The ratio of the reactant and product partial pressures can be used to calculate Kp and Kc for the equilibrium.
Given that the vapor pressure of naphthalene at 27ºC is 0.10 mm Hg, which is equivalent to 0.100 atm, the partial pressure of the gaseous reactant C₁₀H₈(g) can be assumed to be 0.100 atm. The ratio of the partial pressures of the gaseous reactant and product is therefore 0.100/10.00 = 0.01. Using this ratio, we can calculate the equilibrium constant Kp by multiplying the given value of Kc by the ratio: Kp = Kc * 0.01.
The correct answer is option D: 5.34x10⁻⁶, 1.82x10⁻⁴.
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