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Answer :
To find the potential energy of the bicycle at the top of the hill, we use the formula for gravitational potential energy:
[tex]\[ PE = m \cdot g \cdot h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms)
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth)
- [tex]\( h \)[/tex] is the height above the ground (in meters)
Let's plug in the given values:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \, \text{kg} \)[/tex].
- The height [tex]\( h \)[/tex] is [tex]\( 3 \, \text{m} \)[/tex].
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{J} \)[/tex]. So the correct answer is 735 J.
[tex]\[ PE = m \cdot g \cdot h \][/tex]
Where:
- [tex]\( m \)[/tex] is the mass of the object (in kilograms)
- [tex]\( g \)[/tex] is the acceleration due to gravity (approximately [tex]\( 9.8 \, \text{m/s}^2 \)[/tex] on Earth)
- [tex]\( h \)[/tex] is the height above the ground (in meters)
Let's plug in the given values:
- The mass [tex]\( m \)[/tex] of the bicycle is [tex]\( 25 \, \text{kg} \)[/tex].
- The height [tex]\( h \)[/tex] is [tex]\( 3 \, \text{m} \)[/tex].
- The acceleration due to gravity [tex]\( g \)[/tex] is [tex]\( 9.8 \, \text{m/s}^2 \)[/tex].
Now, calculate the potential energy:
[tex]\[ PE = 25 \, \text{kg} \times 9.8 \, \text{m/s}^2 \times 3 \, \text{m} \][/tex]
[tex]\[ PE = 735 \, \text{Joules} \][/tex]
Therefore, the potential energy of the bicycle at the top of the hill is [tex]\( 735 \, \text{J} \)[/tex]. So the correct answer is 735 J.
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