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Answer :
Using the given masses the energy released by the given reaction is approximately 6.95×10¹⁴ joules.
To compute the energy released by the above reaction, we must first estimate the mass change and then use Einstein's mass-energy equivalency formula, E = mc².
Here, it is given that:
Mass of Cf-252 = 4.185815×10⁻²⁵ kg
Mass of Mo-102 = 1.692220×10⁻²⁵ kg
Mass of Ba-147 = 2.439856×10⁻²⁵ kg
Mass of neutron = 1.67490×10⁻²⁷ kg
Δm = (Mass of Cf-252) - (Mass of Mo-102 + Mass of Ba-147 + 3 * Mass of neutron)
Δm = (4.185815×10⁻²⁵ kg) - (1.692220×10⁻²⁵ kg + 2.439856×10⁻²⁵ kg + 3 * 1.67490×10⁻²⁷ kg)
Δm = 2.439819×10⁻²⁵ kg
E = (2.439819×10⁻²⁵ kg) * (3.00×10⁸ m/s)²
Calculating this:
E ≈ 6.95×10¹⁴ joules
Thus, the energy released by the given reaction is approximately 6.95×10¹⁴ joules.
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