Suppose a radioactive nucleus has a half-life of 2 minutes, and the counting rate at time [tex]t = 0[/tex] is 3000 counts per 10 seconds.

Question

21-01-2024
Physics

High School

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Suppose a radioactive nucleus has a half-life of 2 minutes, and the counting rate at time [tex]t = 0[/tex] is 3000 counts per 10 seconds.

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amrya amrya · Answer 1 · 2024-12-01T07:01:19-05:00

Final answer:

The problem pertains to radioactive decay which follows first-order kinetics. Each radioactive nucleus has a half-life representing the time for the sample to decay by half, and the decay rate can be calculated based on this half-life.

Explanation:

The given problem involves understanding the process of radioactive decay, which applies to radioactive isotopes that change over time. This phenomenon follows first-order kinetics, in which each radioactive nuclide has a characteristic half-life, representing the time required for half the atoms in a sample to decay.

In this case, the radioactive nucleus has a half-life of 2 minutes, and the counting rate is given as 3000 counts per 10 seconds, at time t = 0. Since the decay follows first-order kinetics, it is possible to express the decay constant in terms of the half-life, t1/2.

The decay of unstable radioisotopes is exponential with a half-life of T1/2. It's worth noting that the number of radioactive nuclei reduces rapidly in the first few moments of decay, which is consistent with the radioactive decay law.

Learn more about Radioactive Decay here:

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