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Answer :
Let's go through the problem step by step to find the correct solution.
We are given two consecutive exterior angles with measures [tex]\(3x + 50\)[/tex] and [tex]\(7x + 30\)[/tex]. The original solution attempts to set these angles equal, but that's incorrect. In reality, for exterior angles in a polygon, the sum of two consecutive exterior angles should be 360 degrees.
Here's how we should approach the problem:
1. Set up the equation:
[tex]\[
(3x + 50) + (7x + 30) = 360
\][/tex]
2. Combine like terms:
- Combine the [tex]\(x\)[/tex] terms: [tex]\(3x + 7x = 10x\)[/tex]
- Combine the constant terms: [tex]\(50 + 30 = 80\)[/tex]
Therefore, the equation becomes:
[tex]\[
10x + 80 = 360
\][/tex]
3. Solve for [tex]\(x\)[/tex]:
- Subtract 80 from both sides to isolate terms with [tex]\(x\)[/tex]:
[tex]\[
10x = 360 - 80
\][/tex]
[tex]\[
10x = 280
\][/tex]
- Divide both sides by 10 to find [tex]\(x\)[/tex]:
[tex]\[
x = \frac{280}{10}
\][/tex]
[tex]\[
x = 28
\][/tex]
So, the correct value of [tex]\(x\)[/tex] is 28.
We are given two consecutive exterior angles with measures [tex]\(3x + 50\)[/tex] and [tex]\(7x + 30\)[/tex]. The original solution attempts to set these angles equal, but that's incorrect. In reality, for exterior angles in a polygon, the sum of two consecutive exterior angles should be 360 degrees.
Here's how we should approach the problem:
1. Set up the equation:
[tex]\[
(3x + 50) + (7x + 30) = 360
\][/tex]
2. Combine like terms:
- Combine the [tex]\(x\)[/tex] terms: [tex]\(3x + 7x = 10x\)[/tex]
- Combine the constant terms: [tex]\(50 + 30 = 80\)[/tex]
Therefore, the equation becomes:
[tex]\[
10x + 80 = 360
\][/tex]
3. Solve for [tex]\(x\)[/tex]:
- Subtract 80 from both sides to isolate terms with [tex]\(x\)[/tex]:
[tex]\[
10x = 360 - 80
\][/tex]
[tex]\[
10x = 280
\][/tex]
- Divide both sides by 10 to find [tex]\(x\)[/tex]:
[tex]\[
x = \frac{280}{10}
\][/tex]
[tex]\[
x = 28
\][/tex]
So, the correct value of [tex]\(x\)[/tex] is 28.
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