High School

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Error Analysis (G.CO.C.9 SMP #3)

A student is given the following problem:

Two consecutive exterior angles have measures of [tex]3x + 50[/tex] and [tex]7x + 30[/tex]. What is the value of [tex]x[/tex]?

Their work is shown below; however, they have made an error. (Hint: Use the diagram)

[tex]
\begin{array}{l}
3x + 50 = 7x + 30 \\
-7x \quad -7x \\
-4x + 50 = 30 \\
-50 \quad -50 \\
\frac{-4x}{-4} = \frac{-20}{-4} \\
x = 5
\end{array}
[/tex]

Identify and correct the error in the student's solution.

**Solution:**

The error is in the setup of the equation. The measures of two consecutive exterior angles should add up to [tex]180^\circ[/tex], not be equal to each other.

Correct setup:

[tex]
3x + 50 + 7x + 30 = 180
[/tex]

Simplify and solve for [tex]x[/tex]:

[tex]
10x + 80 = 180 \\
10x = 100 \\
x = 10
[/tex]

Therefore, the correct value of [tex]x[/tex] is 10.

Answer :

Let's go through the problem step by step to find the correct solution.

We are given two consecutive exterior angles with measures [tex]\(3x + 50\)[/tex] and [tex]\(7x + 30\)[/tex]. The original solution attempts to set these angles equal, but that's incorrect. In reality, for exterior angles in a polygon, the sum of two consecutive exterior angles should be 360 degrees.

Here's how we should approach the problem:

1. Set up the equation:
[tex]\[
(3x + 50) + (7x + 30) = 360
\][/tex]

2. Combine like terms:
- Combine the [tex]\(x\)[/tex] terms: [tex]\(3x + 7x = 10x\)[/tex]
- Combine the constant terms: [tex]\(50 + 30 = 80\)[/tex]

Therefore, the equation becomes:
[tex]\[
10x + 80 = 360
\][/tex]

3. Solve for [tex]\(x\)[/tex]:
- Subtract 80 from both sides to isolate terms with [tex]\(x\)[/tex]:
[tex]\[
10x = 360 - 80
\][/tex]
[tex]\[
10x = 280
\][/tex]

- Divide both sides by 10 to find [tex]\(x\)[/tex]:
[tex]\[
x = \frac{280}{10}
\][/tex]
[tex]\[
x = 28
\][/tex]

So, the correct value of [tex]\(x\)[/tex] is 28.

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