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An elevator descends into a mine shaft at the rate of 7 meters per minute. If the distance starts from 10 meters above ground level, how long will it take to reach -480 meters?

A) 80 minutes
B) 70 minutes
C) 60 minutes
D) 50 minutes

Answer :

Final answer:

To calculate the time it takes for an elevator descending at 7 m per minute to reach -480 meters from 10 meters above ground, total distance traveled is -490 meters. Dividing this by the speed gives a time of 70 minutes, which is option B.

Explanation:

The question involves calculating the time it takes for an elevator to descend into a mine shaft given a constant speed and starting position above ground level. Since the elevator descends at a rate of 7 m per minute, we need to find out how many minutes it would take to reach -480 meters from a starting point of 10 meters above ground level.

The total distance the elevator needs to travel is the difference between its final position and its starting position:

Total distance to descend = Final position - Starting position

Total distance to descend = -480 m - 10 m = -490 m

Since the distance is negative, it indicates that the elevator is moving downward. We divide the total distance by the speed of the elevator to find the time:

Time = Total distance / Speed

Time = -490 m / -7 m/min = 70 minutes

Therefore, it would take 70 minutes for the elevator to reach -480 meters, which corresponds to answer choice B.

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