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Answer :
Final answer:
The toy rocket, launched with an initial velocity of 128 feet per second, will take 4 seconds to return to the ground. We solved this by using the given height-time equation and setting the height to zero to represent landing.
Explanation:
The subject of this question is Physics, specifically projectile motion. To determine how long it will take for the rocket to return to the ground, we need to find when h(t) is equal to zero, which will be when the toy rocket has landed. This is a quadratic equation in the form of at² + bt + c = 0. The coefficients are a = -16 (which represents half the acceleration due to gravity in ft/s²), b = 128 (the initial velocity in ft/s), and c = 0 (the initial height). To find time when the rocket lands, we need to solve for t in the quadratic equation which is given as t = -b/2a. Inserting the givens, we get t = -128 / (2*-16). So, the answer will be t = 4 seconds. Therefore, the toy rocket will take 4 seconds to hit the ground after it was launched.
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Answer:
t = 2.82 seconds is the time the rocket launches and returns back to Earth.
Step-by-step explanation:
h(t)= -16t² +128t is telling us the height (h) of the rocket as a function of time (t). It is a quadratic equation and will result in a parabola that starts and stops at (0,0), since it is launched vertically and air resistance (and wind, we assume) is neglected.
We want the time, t, such that h(t) is 0. It has reached ground again.
h(t)= -16t² +128t
0 = -16t² +128t Find t such that h(t) is zero.
-16t² +128t = 0
-16t(t² - 8) = 0
t² - 8 = 0 t = [tex]\sqrt{8}[/tex], or 2.82 sec
and -16t = 0 t = 0 sec
t is either 0 or 2.82
Time of zero means the rocket hasn't launched, so we can disregard that value of t.
t = 2.82 seconds is the time the rocket launches and returns back to Earth. Watch out Musk and Bezos.