High School

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A car accelerated from 88 feet per second (fps) to 220 fps in exactly 3 seconds. Assuming the acceleration was constant, what was the car's acceleration, in feet per second per second, from 88 fps to 220 fps?

F. [tex]\quad \frac{1}{44}[/tex]

G. [tex]29 \frac{1}{3}[/tex]

H. 44

J. [tex]75 \frac{1}{3}[/tex]

K. [tex]102 \frac{2}{3}[/tex]

Answer :

Sure, let's solve this step-by-step!

1. Identify the Problem:
- We need to find the constant acceleration of a car that increases its speed from 88 feet per second (fps) to 220 feet per second (fps) in 3 seconds.

2. Formula for Constant Acceleration:
- The formula to calculate acceleration (a) when you know the initial velocity (Vi), final velocity (Vf), and the time (t) is:
[tex]\[
a = \frac{Vf - Vi}{t}
\][/tex]

3. Plug in the Values:
- Initial velocity (Vi) = 88 fps
- Final velocity (Vf) = 220 fps
- Time (t) = 3 seconds

4. Calculate the Acceleration:
- Using the formula:
[tex]\[
a = \frac{220 \, \text{fps} - 88 \, \text{fps}}{3 \, \text{s}}
\][/tex]
- Simplify the numerator:
[tex]\[
220 - 88 = 132
\][/tex]
- Divide by the time:
[tex]\[
a = \frac{132}{3} = 44 \, \text{feet per second squared}
\][/tex]

5. Conclusion:
- The car's acceleration is 44 feet per second per second.

So, the correct answer is H. 44.

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