High School

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What is the value of [tex]102 \times 102 \times 102[/tex] using the identity [tex](a + b)^3[/tex], where [tex]a = 100[/tex] and [tex]b = 2[/tex]?

A) 1,061,208
B) 1,061,128
C) 1,011,208
D) 1,161,208

Answer :

Final answer:

The value of 102 x 102 x 102 is 1,061,208. The student may have misapplied the identity of (a+b)^3, which led to a confusion in their attempt.

Explanation:

The problem involves the mathematical identity of (a + b)^3, which expands to a^3 + 3a^2b + 3ab^2 + b^3. Given that a = 100 and b = 2, substitute these values into the identity to obtain:

100^3 + 3*100^2*2 + 3*100*2^2 + 2^3 = 1,000,000 + 600,000 + 1,200 + 8 = 1,601,208

However, the correct calculation should be the cube of 'a+b' i.e., (a+b)^3 = (100 + 2)^3 = 102^3 = 1,061,208.

Therefore, it appears there has been a misunderstanding with implementing the identity (a+b)^3. The correct value of 102 x 102 x 102 equals 1,061,208 which is answer option A) 1,061,208.

Learn more about Cube of a Number here:

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