Suppose a thistle tube containing a 10% sugar solution is covered at one end by a differentially permeable membrane and is placed in a beaker containing a 5% sugar solution. What will happen to the water?

Question

11-01-2024
Biology

High School

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Suppose a thistle tube containing a 10% sugar solution is covered at one end by a differentially permeable membrane and is placed in a beaker containing a 5% sugar solution. What will happen to the water?

Answer :

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RobinMosby RobinMosby · Answer 1 · 2024-06-03T20:03:08-04:00

Final answer:

The described process is osmosis where water moves from an area of lower solute concentration (5% sugar solution in beaker) to an area of higher solute concentration (10% sugar solution in the thistle tube). This is a crucial process in cell biology for maintaining internal conditions.

Explanation:

This scenario describes a process called osmosis, which occurs when different concentrations of solvents (in this case, sugar solutions) exist on either side of a differentially permeable membrane. Osmosis is the movement of water from an area of lower solute concentration to an area of higher solute concentration. Thus, in this case, water will move from the beaker (less concentrated solution - 5% sugar solution) to the thistle tube (more concentrated solution - 10% sugar solution). This happens until an equilibrium is reached (when concentrations are equal on both sides). This phenomenon is crucial in cell biology as it helps in maintaining the cell's volume and internal conditions.

Learn more about Osmosis here:

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