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A particle with a mass of 1.85 kg oscillates horizontally at the end of a horizontal spring. A student measures an amplitude of 0.851 m and a duration of 131 s for 67 oscillation cycles.

Find the frequency of oscillation.

Answer :

Final answer:

The frequency of oscillation for a particle with a mass of 1.85 kg undergoing 67 cycles in 131 seconds is approximately 0.5115 Hz.

Explanation:

The frequency of oscillation is found by dividing the number of oscillation cycles by the total time it takes to complete those cycles.

In this case, a particle with a mass of 1.85 kg completes 67 oscillation cycles in 131 seconds.

We calculate the frequency (f) by the formula f = number of cycles / time.

Frequency f = 67 cycles / 131 s

Therefore, the frequency is approximately 0.5115 Hz.

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