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Answer :
Final answer:
The activity of 2 mg of Au-198 is 2 mg.
Explanation:
The half-life of a radioactive isotope refers to the amount of time it takes for half of the initial sample to decay. In this case, the half-life of Au-198 is 3 days. To find the activity of 2 mg of Au-198, you can use the equation:
[tex]Activity = Initial mass * (1/2)^(t / half-life)[/tex]
Plugging in the values, we get:
[tex]Activity = 2 mg * (1/2)^(0 / 3)[/tex]
[tex]Activity = 2 mg[/tex]
Therefore, the activity of 2 mg of Au-198 is 2 mg.
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Final answer:
The activity of 2 mg of Au-198 is 2 mg.
Explanation:
The half-life of a radioactive isotope refers to the amount of time it takes for half of the initial sample to decay. In this case, the half-life of Au-198 is 3 days. To find the activity of 2 mg of Au-198, you can use the equation:
[tex]Activity = Initial mass * (1/2)^(t / half-life)[/tex]
Plugging in the values, we get:
[tex]Activity = 2 mg * (1/2)^(0 / 3)[/tex]
[tex]Activity = 2 mg[/tex]
Therefore, the activity of 2 mg of Au-198 is 2 mg.
