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Neglecting air resistance and the weight of the propellant, determine the work done in propelling a four-ton satellite to the following heights. Use 4000 miles as the radius of Earth. Round your answers to one decimal place.

(a) 100 miles above Earth

(b) 700 miles above Earth

Answer :



The work done in propelling a four-ton satellite to various heights neglecting air resistance and the weight of the propellant can be calculated using the equation:
Work = mgh

where m is the mass of the satellite, g is the acceleration due to gravity, and h is the height of the satellite above Earth. The acceleration due to gravity can be calculated using the equation:
g = G * M/R^2

where G is the gravitational constant, M is the mass of the Earth, and R is the radius of the Earth. For this problem, M = [tex]5.97 x 10^24[/tex] kg and R =[tex]6.37 x 10^6 m.[/tex]

For (a) 100 miles above Earth:
h = 100 miles = 160934 m
g = 9.82 m/s^2
m = 4 tons = 4000 kg

Work = mgh = [tex]4000 x 9.82 x 160934 = 6.22 x 10^9 J[/tex](1 decimal place)

For (b) 700 miles above Earth:
h = 700 miles = 1126542 m
g = 9.82 m/s^2
m = 4 tons = 4000 kg

Work = mgh = [tex]4000 x 9.82 x 1126542 = 4.54 x 10^10 J[/tex] (1 decimal place)

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