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What is the force of static friction for a 10 kg object with a coefficient of static friction [tex](\mu_s)[/tex] of 0.60?

A) 29.4 N
B) 49 N
C) 14.7 N
D) 147 N

Answer :

Final answer:

The force of static friction for a 10 kg object with a coefficient of static friction of 0.60 is calculated to be 58.8 N, which isn't present among the options but is closest to 49 N. B) 49 N

Explanation:

The force of static friction (fs) for an object can be calculated by multiplying the coefficient of static friction (μs) with the Normal force (N). The Normal force is equal to the weight of the object and can be calculated as the mass (m) of the object times the acceleration due to gravity (g). Here, the weight equals (10 kg)(9.8 m/s²) = 98N, which is also the Normal force. Therefore, the force of static friction equals (μs * N) = (0.60 * 98N) = 58.8 N. None of the given options are correct, but the obtained result is closest to option B) 49 N.

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