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Answer :
When the man raises both arms from dangling down to straight up, he elevates his center of gravity by 0.35 meters.
To calculate the change in the center of gravity, we need to determine the initial and final positions of the center of gravity. Assuming the arms initially hang down by the sides, and when raised straight up, the arms are perpendicular to the ground.
The change in the center of gravity can be calculated using the formula:
Δh = [tex]h_{\text{final}} - h_{\text{initial}}[/tex]
where Δh is the change in height of the center of gravity.
The initial height of the center of gravity is the distance from the ground to the center of the cylinder, which is half the length of the cylinder:
[tex]h_{\text{initial}} = 0.5 \times \text{length} = 0.5 \times 70 \, \text{cm} = 35 \, \text{cm} = 0.35 \, \text{m}[/tex]
The final height of the center of gravity is the height of the man's raised arms, which is the total length of the man's arm:
[tex]h_{\text{final}} = \text{length} = 70 \, \text{cm} = 0.70 \, \text{m}[/tex]
Now we can calculate the change in the center of gravity:
[tex]\Delta h = h_{\text{final}} - h_{\text{initial}} = 0.70 \, \text{m} - 0.35 \, \text{m} = 0.35 \, \text{m}[/tex]
Therefore, the man raises his center of gravity by 0.35 meters when raising both arms from hanging down to straight up.
To know more about the center of gravity refer here :
https://brainly.com/question/20662235#
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