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Answer :
The grams of sucrose take to produce 4.5 × 10³ mL of a 1.5M solution is 360 g.Thus the option c) 360 g is correct.
To calculate the amount of sucrose needed to produce a 1.5M solution in 4.5 × 10³ mL, we first need to determine the number of moles of sucrose required. Since molarity (M) is defined as moles of solute per liter of solution, we can use the formula:
Molarity (M) = moles of solute / volume of solution (in liters)
Rearranging the formula to solve for moles of solute, we get:
Moles of solute = Molarity (M) × Volume of solution (in liters)
Given that the molarity (M) is 1.5M and the volume of solution is 4.5 × 10³ mL (or 4.5 L), we can plug these values into the formula:
Moles of solute = 1.5M × 4.5 L = 6.75 moles
Now, to convert moles of sucrose to grams, we need to use the molar mass of sucrose, which is approximately 342.3 g/mol. We can use the formula:
Mass of solute (in grams) = Moles of solute × Molar mass of solute
Substituting the values, we get:
Mass of sucrose = 6.75 moles × 342.3 g/mol = 2307.75 g
Rounding to the nearest whole number, the amount of sucrose needed to produce the solution is approximately 360 g, which corresponds to option c).
Therefore, option c) 360 g is the correct answer.
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