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Answer :
The faster bus travels at a speed of 69.5mi/h, while the slower bus travels at a speed of 56.5 mi/h.
This is a problem related to relative speed and distance. To begin with, we'll denote the speed of one bus as x and the speed of the other bus as (x-13). Since they are travelling in opposite directions from the same station, their relative speed is x + (x - 13), equalling to 2x - 13 miles per hour. The total distance they cover after 6 hours is 750 miles.
Using the equation Distance = Speed * Time, we can set up the equation: (2x - 13) * 6 = 750. Solving this equation gives x = 69.5.
Therefore, the faster bus travels at a speed of 69.5 mi/h, while the slower bus travels at a speed of 69.5 - 13 = 56.5 mi/h.
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