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Answer :
The force required to push the bobsled down the incline and achieve a speed of 67 km/h at the end of 75 m is 236.8 N.
The force required to push the bobsled down the incline can be found using the equation:
F = (mgsinθ + mgμcosθ) / (1 - μsinθ)
where F is the force required, m is the mass of the bobsled, g is the acceleration due to gravity, θ is the angle of the incline, and μ is the coefficient of kinetic friction.
Plugging in the given values, we get:
F = (25 kg * 9.81 m/s² * sin(6°) + 25 kg * 9.81 m/s² * 0.10 * cos(6°)) / (1 - 0.10 * sin(6°))
= 236.8 N
To achieve a speed of 67 km/h at the end of 75 m, we need to find the acceleration of the bobsled using the equation:
v² = u² + 2as
where v is the final velocity (67 km/h = 18.61 m/s), u is the initial velocity (0 m/s), a is the acceleration, and s is the distance traveled (75 m).
Solving for a, we get:
a = (v² - u²) / (2*s)
= (18.61 m/s)² / (2 * 75 m)
= 4.90 m/s²
As a result, the power necessary to drive the bobsled down the hill and reach a speed of 67 km/h at the end of 75 meters is 236.8 N.
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