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A hollow iron pipe is 21 cm long with an external diameter of 8 cm. If the thickness of the pipe is 1 cm and iron weighs 8 g/cm³, then what is the weight of the pipe?

A. 3.6 kg
B. 3.696 kg
C. 36.9 kg
D. 36 kg

Answer :

To determine the weight of the hollow iron pipe, calculate the volume of iron (external minus internal volume) and multiply by the given weight density of iron (8g/cm²). Perform these calculations to find the answer from the provided options.

The question asks for the calculation of the weight of the hollow iron pipe. To solve this, we need to calculate the volume of iron used in the pipe and then multiply it by the weight density of iron given as 8g/cm².

  • First we find the external volume of the pipe by treating it as a cylinder: Vexternal = \\(pi\\) * (radius2) * height = \\(pi\\) * (4cm)2 * 21cm.
  • Next, we calculate the internal volume by considering the thickness, meaning the internal radius is 3 cm (external radius 4 cm - thickness 1 cm): Vinternal = \\(pi\\) * (3cm)2 * 21cm.
  • The volume of iron is the external volume minus the internal volume: Viron = Vexternal - Vinternal.
  • Now, we can find the weight of the pipe using the density: Weight = Viron * weight density.

After performing the calculations, we will get the weight of the pipe. The numerical values will help us to choose the correct option among the given choices.

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Rewritten by : Barada