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250 mg of MgCO3×xCHCl3 is heated and the decomposition is followed by TGA (Thermo-Gravimetric Analyses). Two decomposition steps are visible, the first between 50 and 100 °C corresponding to a 58 % loss of CHCl3), and the second between 600 and 800 °C corresponding to a loss of 22%. Determine the value of "x".

(ii) Determine what molecule is released in the second decomposition step.

(iii) Determine the final product that is formed

Answer :

Final answer:

The value of 'x' is determined by calculating the number of CHCl3 molecules bonded to MgCO3. Ethyl Chloride (CHCl3) is released in the second decomposition step, and the final product is MgO.

Explanation:

x is the number of CHCl3 molecules bonded to one unit of MgCO3.

During the first decomposition step, 58% of the CHCl3 is lost. This corresponds to the loss of 0.58x molecules of CHCl3.

During the second decomposition step, 22% of the remaining CHCl3 is lost. This corresponds to the loss of 0.22(1-0.58x) molecules of CHCl3.

The final product of the decomposition is MgO.

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