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Multiply: [tex](9x + 7)(3x^2 + 5x - 1)[/tex]

A. [tex]3x^2 + 14x + 6[/tex]

B. [tex]27x^3 + 66x^2 + 26x - 7[/tex]

C. [tex]27x^3 + 45x^2 - 7[/tex]

D. [tex]27x^3 + 66x^2 + 44x + 7[/tex]

Answer :

Sure, let's go through the detailed step-by-step solution to multiply [tex]\((9x + 7)\)[/tex] by [tex]\( (3x^2 + 5x -1)\)[/tex].

We can use the distributive property (also known as the FOIL method when applied to binomials) to expand the multiplication. Here's the step-by-step breakdown:

1. Multiply each term in [tex]\(9x + 7\)[/tex] by each term in [tex]\(3x^2 + 5x - 1\)[/tex]:

[tex]\[
(9x + 7)(3x^2 + 5x - 1)
\][/tex]

2. Distribute [tex]\(9x\)[/tex] to each term in [tex]\(3x^2 + 5x - 1\)[/tex]:

[tex]\[
9x \cdot 3x^2 + 9x \cdot 5x + 9x \cdot (-1)
\][/tex]

[tex]\[
= 27x^3 + 45x^2 - 9x
\][/tex]

3. Distribute [tex]\(7\)[/tex] to each term in [tex]\(3x^2 + 5x - 1\)[/tex]:

[tex]\[
7 \cdot 3x^2 + 7 \cdot 5x + 7 \cdot (-1)
\][/tex]

[tex]\[
= 21x^2 + 35x - 7
\][/tex]

4. Combine all the terms from the two distributions:

[tex]\[
27x^3 + 45x^2 - 9x + 21x^2 + 35x - 7
\][/tex]

5. Group and combine like terms:

[tex]\[
27x^3 + (45x^2 + 21x^2) + (-9x + 35x) - 7
\][/tex]

[tex]\[
= 27x^3 + 66x^2 + 26x - 7
\][/tex]

So, the final expanded and simplified form of [tex]\((9x + 7)(3x^2 + 5x - 1)\)[/tex] is:

[tex]\[
27x^3 + 66x^2 + 26x - 7
\][/tex]

Hence, among the provided options, the correct answer is:

[tex]\[
27x^3 + 66x^2 + 26x - 7
\][/tex]

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