A 56.7-µF capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is 4.36 V and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches 15.7 A.

As the generator frequency is increased, at what frequency will the fuse burn out?

Question

25-02-2025
Physics

High School

We appreciate your visit to A 56 7 µF capacitor is connected to a generator operating at a low frequency The rms voltage of the generator is 4 36 V. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

A 56.7-µF capacitor is connected to a generator operating at a low frequency. The rms voltage of the generator is 4.36 V and is constant. A fuse in series with the capacitor has negligible resistance and will burn out when the rms current reaches 15.7 A.

As the generator frequency is increased, at what frequency will the fuse burn out?

Answer :

Other Questions

How many feet are in 65 inches?

What was this structure most likely used for? creating terraces for farm

If [tex]$f(x)$[/tex] is the height, in cm, of a sunflower plant that

Responde las siguientes preguntas: ¿Cuántos centímetros cúbicos equivalen a 1 dm³?

Mary bought 10 quarts of juice at the grocery. How many gallons

Select the statement that indicates a preference for English class. A. I

What is the number of protons, neutrons, and electrons for the isotope

The phrases "sound lines" and "amply provides" help make which argument? A.

Used to move clients in bed, one person on each side: A.

A recent survey of 8, 000 high school students found that the

priyankakasturiase50 priyankakasturiase50 · Answer 1 · 2024-08-31T04:46:30-04:00

Final answer:

The question asks for the frequency at which a 56.7 µF capacitor in an AC circuit will cause a fuse to burn out due to excessive rms current when the rms voltage is constant at 4.36 V. Using the formulas for capacitive reactance and rms current, we can solve for the frequency that results in a current of 15.7 A.

Explanation:

The question pertains to finding the frequency at which a capacitor in an AC circuit will cause a fuse to burn out due to excessive rms current. If the capacitor has a capacitance of 56.7 µF and is connected to a generator with a constant rms voltage of 4.36 V, we can calculate the frequency at which the rms current will reach the threshold of 15.7 A using the formula for capacitive reactance (Xc) and the formula for rms current in terms of voltage and reactance. The capacitive reactance is given by Xc = 1 / (2πfC), and the rms current (Irms) is Vrms / Xc. By plugging in the known values and solving for the frequency f, we can find the frequency that will cause the rms current to exceed the fuse's limit.