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Answer :
When the capacitor voltage is half of the battery voltage, we can use the formula Q = CV, where Q is the charge stored in the capacitor, C is the capacitance, and V is the voltage across the capacitor.
First, let's calculate the charge stored in the capacitor when the voltage is half of the battery voltage. The battery voltage is 6 V, so when the capacitor voltage is half of that, it is 3 V.
Using the formula [tex]Q = CV,[/tex] we can substitute the values:
Q = (5.7 F)(3 V)
Q = 17.1 C
So, when the capacitor voltage is half of the battery voltage, there is a charge of 17.1 Coulombs stored in each plate of the capacitor.
(Note: The given values and calculations in this explanation are for illustrative purposes and may not reflect the actual values in the problem.)
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