We appreciate your visit to You are helping with some repairs at home You drop a hammer and it hits the floor at a speed of 12 feet per second. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To find the height from which the hammer was dropped, we can use the formula for the relationship between speed, gravity, and height:
[tex]\[ v = \sqrt{2gh} \][/tex]
where:
- [tex]\( v \)[/tex] is the final speed of the hammer (12 feet per second),
- [tex]\( g \)[/tex] is the acceleration due to gravity (32 feet/second[tex]\(^2\)[/tex]),
- [tex]\( h \)[/tex] is the height from which the hammer was dropped.
We need to solve for [tex]\( h \)[/tex]. Here's how you can do it step-by-step:
1. Start with the formula:
[tex]\[ v = \sqrt{2gh} \][/tex]
2. Square both sides to get rid of the square root:
[tex]\[ v^2 = 2gh \][/tex]
3. Solve for [tex]\( h \)[/tex] by dividing both sides by [tex]\( 2g \)[/tex]:
[tex]\[ h = \frac{v^2}{2g} \][/tex]
4. Plug in the known values ([tex]\( v = 12 \)[/tex] feet/second and [tex]\( g = 32 \)[/tex] feet/second[tex]\(^2\)[/tex]):
[tex]\[ h = \frac{12^2}{2 \times 32} \][/tex]
5. Calculate:
[tex]\[ h = \frac{144}{64} \][/tex]
[tex]\[ h = 2.25 \][/tex]
So, the hammer was dropped from a height of 2.25 feet above the ground. Thus, the correct answer is:
D. 2.25 feet
[tex]\[ v = \sqrt{2gh} \][/tex]
where:
- [tex]\( v \)[/tex] is the final speed of the hammer (12 feet per second),
- [tex]\( g \)[/tex] is the acceleration due to gravity (32 feet/second[tex]\(^2\)[/tex]),
- [tex]\( h \)[/tex] is the height from which the hammer was dropped.
We need to solve for [tex]\( h \)[/tex]. Here's how you can do it step-by-step:
1. Start with the formula:
[tex]\[ v = \sqrt{2gh} \][/tex]
2. Square both sides to get rid of the square root:
[tex]\[ v^2 = 2gh \][/tex]
3. Solve for [tex]\( h \)[/tex] by dividing both sides by [tex]\( 2g \)[/tex]:
[tex]\[ h = \frac{v^2}{2g} \][/tex]
4. Plug in the known values ([tex]\( v = 12 \)[/tex] feet/second and [tex]\( g = 32 \)[/tex] feet/second[tex]\(^2\)[/tex]):
[tex]\[ h = \frac{12^2}{2 \times 32} \][/tex]
5. Calculate:
[tex]\[ h = \frac{144}{64} \][/tex]
[tex]\[ h = 2.25 \][/tex]
So, the hammer was dropped from a height of 2.25 feet above the ground. Thus, the correct answer is:
D. 2.25 feet
Thanks for taking the time to read You are helping with some repairs at home You drop a hammer and it hits the floor at a speed of 12 feet per second. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
