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A 35 pF capacitor is connected to a 12 V battery and allowed to fully charge. The capacitor is then isolated from the battery, and a material with a dielectric constant of 3 is inserted between the plates.

Which of the following is the change in potential difference across the plates of the capacitor as the dielectric is inserted?

A. 0 V
B. 4 V
C. 6 V
D. 0 kV
E. 24 V

Answer :

Final answer:

The change in potential difference across the plates of the capacitor as the dielectric is inserted is a decrease by a factor of 3.

Explanation:

When a dielectric material is inserted between the plates of a capacitor, it affects the capacitance and the potential difference across the plates. The capacitance of a capacitor is given by the formula C = ε₀A/d, where C is the capacitance, ε₀ is the permittivity of free space, A is the area of the plates, and d is the distance between the plates. The permittivity of the dielectric material is represented by εᵣ, which is the dielectric constant.

When a dielectric material with a dielectric constant of 3 is inserted between the plates of the capacitor, the capacitance increases by a factor of 3. This means that the potential difference across the plates of the capacitor decreases by a factor of 3 as well.

Therefore, the change in potential difference across the plates of the capacitor as the dielectric is inserted is a decrease by a factor of 3.

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