We appreciate your visit to Determine the inverse Laplace transform of the function tex F s tex F s frac 4s s 2 82s 258 s 4 s 2 8s. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
To determine the inverse Laplace transform of the given function [tex]F(s) = \frac{4s}{(s^2 + 82s + 258)(s - 4)(s^2 + 8s + 17)}[/tex], we need to work step by step through the process, understanding each part clearly.
First, note that the given function is relatively complex, involving a mixture of quadratic and linear terms. The aim is to express [tex]F(s)[/tex] in a form that can be more easily inverted into the time domain using partial fraction decomposition.
Step-by-step Process:
Factor the Denominator (if possible)
- The denominator is [tex](s^2 + 82s + 258)(s - 4)(s^2 + 8s + 17)[/tex]. Begin by ensuring it’s correctly represented. Check if any factors simplify or break down further, but often these are already in simplest form or need complex numbers.
Partial Fraction Decomposition
- To decompose [tex]F(s)[/tex], express it as a sum of simpler fractions:
[tex]F(s) = \frac{A}{s - 4} + \frac{Bs + C}{s^2 + 8s + 17} + \frac{Ds + E}{s^2 + 82s + 258}[/tex] - Solve for the constants [tex]A, B, C, D,[/tex] and [tex]E[/tex] using methods such as equating coefficients or substituting values for [tex]s[/tex].
- To decompose [tex]F(s)[/tex], express it as a sum of simpler fractions:
Use Known Inverse Transforms
- Once decomposed:
- The term [tex]\frac{A}{s - 4}[/tex] corresponds to an exponentially decaying function [tex]Ae^{4t}[/tex] in the time domain.
- Terms involving quadratic denominators like [tex]\frac{Bs + C}{s^2 + 8s + 17}[/tex] and [tex]\frac{Ds + E}{s^2 + 82s + 258}[/tex] can be written in terms that map onto damped sine/cosine functions.
- Once decomposed:
Combine Results
- After finding the inverse transforms for each decomposed part, combine them to get the complete time domain function [tex]f(t)[/tex].
Considerations:
- Be familiar with standard Laplace transform pairs.
- Each component may correspond to a known pattern such as exponential decay or oscillation, typically represented via cosine and sine functions managed by the quadratic terms.
Unfortunately, without further breakdown of specific components or numeric solutions, the detailed function for [tex]f(t)[/tex] in the time domain requires additional steps in solving [tex]F(s)[/tex] via algebraic manipulation and potentially numeric computation for clarity. Nevertheless, this approach provides a guideline to tackle the inverse Laplace transform process for the provided function.
Thanks for taking the time to read Determine the inverse Laplace transform of the function tex F s tex F s frac 4s s 2 82s 258 s 4 s 2 8s. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada