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Answer :
Final answer:
To make a 35.0 wt% SrCl₂ solution using 36.0 grams of SrCl₂, you'll need 66.9 grams of water. Therefore the correct option is b).
Explanation:
You are asked how much water must be added to 36.0 grams of SrCl₂ to produce a solution that is 35.0 wt% SrCl₂. To find the answer, you can use the formula for weight percent (wt%):
wt% = (mass of solute / (mass of solute + mass of solvent)) * 100%
In this case, the mass of SrCl₂ (solute) is 36.0 grams, and you want to find the mass of water (solvent) needed to achieve a 35.0 wt% concentration.
35.0 = (36.0 / (36.0 + mass of water)) * 100
Solving for mass of water, we get:
mass of water = (36.0 / 0.35) - 36.0
= 66.9 grams
So, option b) 66.9 g of water is needed.
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