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How much water must be added to 36.0 grams of SrCl₂ to produce a solution that is 35.0 wt% SrCl₂?

A. 48.6 g
B. 66.9 g
C. 103 g
D. 97.2 g

Answer :

Final answer:

To make a 35.0 wt% SrCl₂ solution using 36.0 grams of SrCl₂, you'll need 66.9 grams of water. Therefore the correct option is b).

Explanation:

You are asked how much water must be added to 36.0 grams of SrCl₂ to produce a solution that is 35.0 wt% SrCl₂. To find the answer, you can use the formula for weight percent (wt%):

wt% = (mass of solute / (mass of solute + mass of solvent)) * 100%

In this case, the mass of SrCl₂ (solute) is 36.0 grams, and you want to find the mass of water (solvent) needed to achieve a 35.0 wt% concentration.

35.0 = (36.0 / (36.0 + mass of water)) * 100

Solving for mass of water, we get:

mass of water = (36.0 / 0.35) - 36.0

= 66.9 grams

So, option b) 66.9 g of water is needed.

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