A runaway 185 kg wheeled skip is rolling east along a road with a velocity of +2.2 m/s. A 2560 kg car moving west with a velocity of −9.7 m/s hits the skip. After the collision, the skip is moving west with a velocity of −14.4 m/s. What is the velocity of the car after the collision?

Question

24-02-2024
Physics

High School

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A runaway 185 kg wheeled skip is rolling east along a road with a velocity of +2.2 m/s. A 2560 kg car moving west with a velocity of −9.7 m/s hits the skip. After the collision, the skip is moving west with a velocity of −14.4 m/s. What is the velocity of the car after the collision?

Answer :

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ahujagaitry ahujagaitry · Answer 1 · 2025-01-05T16:59:01-05:00

Final answer:

Using the law of conservation of momentum, we find out that the velocity of the car after colliding with the skip is -4.76 m/s to the west.

Explanation:

The primary concept in this question is the law of conservation of momentum which states that the total momentum of a system of objects is conserved, unless acted upon by external forces. In this case, the two objects are the skip and the car. This principle can be mathematically expressed as: m1v1 + m2v2 = m1v'1 + m2v'2

Where m1 and v1 are the mass and velocity of the car, m2 and v2 are the mass and velocity of the skip, and v'1 and v'2 are their velocities after the collision. Given the data in the question, we know: m1 = 2560 kg, v1 = -9.7 m/s, m2 = 185 kg, v2 = 2.2 m/s, and v'2 = -14.4 m/s. We want to find v'1, the velocity of the car after the collision.

By substituting in provided values and solving for v'1 in the equation, we can find that the velocity of the car after the collision is -4.76 m/s moving west.

Learn more about conservation of momentum here:

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