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A motorboat sets out in the direction N 62°18' E. The speed of the boat in still water is 36.9 mph. If the current is flowing directly south, and the actual direction of the motorboat is due east, find the speed of the current and the actual speed of the motorboat.

Answer :

Therefore, the speed of the current is 12.8 mph, and the actual speed of the motorboat is 39.7 mph.

To solve this problem, we can use the formula:

v = d/t

where v is the speed of the boat in still water, d is the distance traveled by the boat, and t is the time taken.

Let’s assume that the speed of the current is c and the actual speed of the motorboat is m. Then we can write:

m×cos(62°18') = v + c

m×sin(62°18') = 0

where v = 36.9 mph.

Solving these equations for m and c, we get:

m = 39.7 mph

c = 12.8 mph

Therefore, the speed of the current is 12.8 mph, and the actual speed of the motorboat is 39.7 mph.

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