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Answer :
Answer: 15 / 56
Step-by-step explanation:
Number of red checkers = 3
Number of black checkers = 5
Total number of checkers = 8
P(black, then red) = 5/8 × 3/7 = 15/56
We should note that the probability to pick a black checker first will be 5 out of 8. Then, there'll be 7 checkers left and the probability to pick a res checker will be 3/7. We then multiply the probabality of each together.
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Rewritten by : Barada
To find the probability of selecting a black and then a red checker without replacement from a bag containing 3 red and 5 black checkers, calculate the product of the individual probabilities: (5/8) * (3/7) = 15/56.
The probability of selecting a black checker first and then a red checker from a bag containing 3 red checkers and 5 black checkers without replacement is calculated as follows:
- First, the probability of selecting a black checker: P(Black first) = number of black checkers / total number of checkers = 5/8.
- After removing a black checker, there are now 7 checkers left in the bag, including 3 red ones.
- Then, the probability of selecting a red checker: P(Red second) = number of red checkers / remaining number of checkers = 3/7.
- Finally, the probability of both events happening in succession (black, then red) is the product of the two probabilities: P(Black, then Red) = P(Black first) * P(Red second) = (5/8) * (3/7) = 15/56.
