High School

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For the function [tex]f(x)=45x^3−3x^5[/tex], determine the interval(s) for which [tex]f(x)[/tex] decreases.

A. [tex](-3,0) \cup (3,\infty)[/tex]
B. [tex](-3,0) \cup (0,3)[/tex]
C. [tex](-\infty,-3) \cup (3,\infty)[/tex]
D. [tex](-3,0) \cup (3,\infty)[/tex]

Answer :

Final answer:

The interval(s) for which f(x) decreases for the function f(x) = 45x³−3x⁵ are (-∞, -3) ∪ (3, ∞), which corresponds to option d) (-3,0)∪(3,[infinity]).

Explanation:

To determine the interval(s) for which f(x) decreases for the function f(x) = 45x³−3x⁵, we need to find the values of x where the derivative of f(x) is negative.

  1. Find the derivative of f(x): f'(x) = 135x² - 15x⁴
  2. Set f'(x) less than zero and solve for x. 135x² - 15x⁴ < 0
  3. Factor out x² from the equation: x²(135 - 15x²) < 0
  4. Solve for x. We have two critical points: x = -√9 = -3 and x = √9 = 3

Therefore, the interval(s) for which f(x) decreases are (−∞, -3) ∪ (3, ∞), which corresponds to option d) (−3,0)∪(3,[infinity]).

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