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A ball initially at rest rolls down a hill with an acceleration of 4.3 m/s². If it accelerates for 5.8 seconds, how far will it move?

Answer in units of meters (m).

Answer :

Final answer:

The distance travelled by the ball, which was initially at rest, accelerating down a hill for 5.8 seconds with an acceleration of 4.3 m/s², is approximately 72.29 meters.

Explanation:

The question is asking to find the distance travelled by a ball rolling down a hill. This problem involves the physics concept of linear motion, specifically the equation for motion which states that distance = 0.5 * acceleration * time². The ball was initially at rest, hence initial velocity is zero, and we only focus on the acceleration and time.

So, to solve this, you would insert the provided values into the equation like this: distance = 0.5 * 4.3 m/s² * (5.8 s)². After doing the calculation, you find that the distance travelled by the ball is approximately 72.29 meters.

Learn more about linear motion here:

https://brainly.com/question/32294697

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