High School

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The magnitude of the electric field due to a small charged object is 12.0 N/C at a distance of 301 cm from the charge.

What is the field 6.00 m away from the charge?

A) 4.00 N/C
B) 6.00 N/C
C) 8.00 N/C
D) 12.00 N/C

Answer :

Final answer:

To find the electric field at a distance 6.00 m away from the charge, we can use the inverse square law. The magnitude of the electric field is inversely proportional to the square of the distance from the charge.

Explanation:

To find the electric field at a distance 6.00 m away from the charge, we can use the inverse square law. The magnitude of the electric field is inversely proportional to the square of the distance from the charge.

If the magnitude of the electric field at a distance of 301 cm is 12.0 N/C, we can set up the following equation:

12.0 N/C = k * (q / (0.301 m)^2)

where k is the electrostatic constant and q is the charge of the small object. Rearranging the equation, we can solve for q to find the charge of the object. Once we have the charge, we can calculate the electric field at a distance of 6.00 m using the equation:

E = k * (q / (6.00 m)^2)

Substituting the known values, we can find the electric field at a distance of 6.00 m.

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