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Part A: What is the difference in blood pressure (mm Hg) between the bottom of the feet and the top of the head of a 1.57-meter tall person standing vertically?

Given:
- 1 mm Hg = 133 N/m²
- Density of blood = 1050 kg/m³

(Note: Additional information such as gravitational acceleration might be required to solve this problem.)

Answer :

The blood pressure difference between the feet and head of a 1.81-meter-tall person standing vertically is roughly 138.5 mm-Hg, calculated using hydrostatic pressure principles.

The difference in blood pressure between the bottom of the feet and the top of the head of a 1.81-meter-tall person standing vertically can be calculated using the hydrostatic pressure formula.

Hydrostatic pressure depends on the height of the fluid column, the density of the fluid, and the acceleration due to gravity. Given that 1 mm-Hg is equivalent to 133 N/m² and the density of blood is 1050 kg/m³, the difference in pressure can be calculated as follows:

Pressure difference (in mm-Hg) = height difference (in meters) × density of blood (in kg/m³) × acceleration due to gravity (in m/s²) / 133 N/m²

The person's height is 1.81 meters, and acceleration due to gravity is approximately 9.81 m/s². Substituting these values:

Pressure difference = 1.81 m × 1050 kg/m³ × 9.81 m/s² / 133 N/m² ≈ 138.5 mm-Hg.

Thus, the difference in blood pressure between the bottom of the feet and the top of the head is approximately 138.5 mm-Hg for a 1.81-meter-tall person standing vertically.

Complete question:

What is the difference in blood pressure (mm-Hg) between the bottom of the feet and the top of the head of a 1.81-m-tall person standing vertically? 1 mm-Hg = 133 N/m2. The density of blood is 1050 kg/m3.

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