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1. Order: Codeine sulphate 10 mg PO every 4 hours as needed for pain. The strength of the codeine sulphate is [tex]x \, \text{mg}/5 \, \text{mL}[/tex]. How many mL of this narcotic drug will you administer to the patient?

2. Convert 0.5 mL/min to an equivalent rate in mL/h.

3. Order: Micro-K (potassium chloride) 16 mEq PO stat. How many 8 mEq tablets will you administer?

Answer :

1. Administer 50 mL of codeine sulphate.
2. The equivalent rate of 0.5 mL/min is 30 mL/h.
3. Administer 2 tablets of 8mEq each for the order of Micro - k (potassium chloride) 16mEq po stat.

1. To determine the amount of codeine sulphate in mL that needs to be administered to the patient, we first need to convert the dosage from mg to mL using the given strength of the codeine sulphate, which is Mg/5 mL.

The ordered dosage is 10mg and the strength is Mg/5 mL. We can set up a proportion to find the equivalent mL:

10mg / (Mg/5 mL) = x mL / 1

Cross-multiplying, we get: 10mg * 1 = x mL * (Mg/5 mL)

Simplifying, we have: 10mg = x/5

Multiplying both sides by 5, we find: x = 50 mL

Therefore, 50 mL of the codeine sulphate should be administered to the patient.

2. To convert 0.5 mL/min to an equivalent rate in mL/h, we need to multiply the given rate by 60 since there are 60 minutes in an hour.

0.5 mL/min * 60 min/h = 30 mL/h

Therefore, the equivalent rate of 0.5 mL/min is 30 mL/h.

3. To determine the number of 8mEq tablets to be administered for the order of Micro - k (potassium chloride) 16mEq po stat, we divide the ordered dosage by the strength of each tablet, which is 8mEq.

16mEq / 8mEq = 2 tablets

Therefore, 2 tablets of 8mEq each should be administered for the order of Micro - k (potassium chloride) 16mEq po stat.

In summary, for the given orders:
1. Administer 50 mL of codeine sulphate.
2. The equivalent rate of 0.5 mL/min is 30 mL/h.
3. Administer 2 tablets of 8mEq each for the order of Micro - k (potassium chloride) 16mEq po stat.

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