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Answer :
1. The length of the longer leg is 12 cm.
**Answer:** B.) 12 cm
2. The length of the other leg is 12 units.
**Answer:** D.) 12 units
3. The width of the screen is square root of 245 inches.
**Answer:** C.) 245 in
4. The distance from point A to point B, if walking through the pond, is square root of 3778 meters.
**Answer:** D.) 3778 M
5. The height of the kite from the ground is square root of 121 meters.
**Answer:** D.) 11 M
Let's solve each problem step by step:
1. **First problem:**
Given the shorter leg a = 5 cm and hypotenuse c = 13 cm.
Using the Pythagorean theorem: a^2 + b^2 = c^2
5^2 + b^2 = 13^2
25 + b^2 = 169
b^2 = 169 - 25
b^2 = 144
b = square root of 144 = 12 cm
**Answer:** B.) 12 cm
2. **Second problem:**
Given hypotenuse c = 15 units and leg a = 9 units.
Using the Pythagorean theorem: a^2 + b^2 = c^2
9^2 + b^2 = 15^2
81 + b^2 = 225
b^2 = 225 - 81
b^2 = 144
b = square root of 144 = 12 units
**Answer:** D.) 12 units
3. **Third problem:**
Given diagonal d = 21 inches and height h = 14 inches.
Using the Pythagorean theorem: h^2 + w^2 = d^2
14^2 + w^2 = 21^2
196 + w^2 = 441
w^2 = 441 - 196
w^2 = 245
w = square root of 245
**Answer:** C.) 245 in
4. **Fourth problem:**
The shortest path is the hypotenuse of a right triangle with legs 23 meters and 57 meters.
Using the Pythagorean theorem: a^2 + b^2 = c^2
23^2 + 57^2 = c^2
529 + 3249 = c^2
3778 = c^2
c = square root of 3778
**Answer:** D.) 3778 M
5. **Fifth problem:**
Given horizontal distance d = 60 meters and string length s = 61 meters.
Using Pythagorean theorem: h^2 + d^2 = s^2
h^2 + 60^2 = 61^2
h^2 + 3600 = 3721
h^2 = 3721 - 3600
h^2 = 121
h = square root of 121
**Answer:** D.) 11 M
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