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Answer :
The airplane's angle of elevation from the runway is approximately 17.36 degrees, and the distance between the plane and the ground is 4772.79 ft.
Here are the main answers to the question:
First, we will find the distance between the plane and the ground:5000² = 25000000+ 1500² = 2250000d² = 22750000d = 4772.79 ft.
To find the angle of elevation, we will use the tangent ratio:tan A = opposite/hypotenuse = 1500/4772.79A = tan⁻¹(1500/4772.79)A = 17.36°.
The airplane's angle of elevation from the runway is approximately 17.36 degrees.
In conclusion, the airplane's angle of elevation from the runway is approximately 17.36 degrees, and the distance between the plane and the ground is 4772.79 ft.
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