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Answer :
Final answer:
Upon cooling a saturated solution from 108°C to 25°C, the maximum solute yield cannot exceed the solubility limit at the lower temperature. Hence, the maximum yield of solute would be 33.1 g/100mL, making all provided options incorrect since they exceed this solubility limit.
Explanation:
The solubility of a compound changes with temperature, and a saturated solution will have the maximum amount of solute that can be dissolved at that temperature. If the solution is cooled, the solute will begin to crystallize out of the solution until the solubility limit at the lower temperature is reached.
In the given problem, the solubility of the compound at 108°C is 38.5 g/100mL. If this saturated solution is cooled to 25°C, where the solubility is 33.1 g/100mL, then excess solute will precipitate out until the concentration is at the maximum solubility for 25°C.
Therefore, since the maximum yield at 25°C cannot exceed the solubility at this temperature, the maximum yield that can be obtained by cooling a saturated solution from 108°C to 25°C is 33.1 g/100mL. Consequently, none of the options given (a) 35.8 g/100mL, (b) 36.3 g/100mL, (c) 37.2 g/100mL, (d) 37.8 g/100mL can be correct because they are all higher than the solubility at 25°C.
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