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A regulation racquetball court has a perimeter of 120 ft, with a length that is twice the width. Find the length and the width of the court.

Answer :

Final answer:

The width of a regulation racquetball court is 20ft and its length is 40ft. This is determined by substituting the width into the perimeter equation and solving for the width, then substituting the found width into the length equation.

Explanation:

To solve the problem, we can set up a system of equations. Let's denote the width of the racquetball court as w and its length as l. The information given tells us two things:

  • l = 2w. (The length is twice the width.)
  • 2l + 2w = 120. (The perimeter of the court which results from adding two widths and two lengths is 120 ft.)

We can substitute the first equation into the second one to find the values of w and l. This results in: 2*(2w) + 2w = 120 which simplifies to 6w = 120. Solving this equation, we find w = 20ft. Substituting w = 20 back into the first equation l = 2w, we find l = 2*20 = 40ft.

So, the regulation racquetball court has a width of 20ft and a length of 40ft.

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