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Answer :
Final answer:
The concentration of NaCl in a 7.5 mL salt pod with a molarity of 1.55M doesn't change and remains 1.55M, because molarity is a concentration, expressed as amount of solute per liter of solution.
Explanation:
The question asks about the concentration of NaCl in a 7.5 mL salt pod with a molarity of 1.55M. To solve this problem, we apply the formula of molarity which is moles of solute per liters of solution. Here we have volume in mL, so we need to convert it to liters. 1 liter = 1000 mL, so 7.5 mL = 0.0075 liters.
We can calculate moles of NaCl using molarity. As Molarity (M) = moles/Liter, then moles = Molarity x Volume = 1.55 Mol/L x 0.0075 L = 0.011625 mol.
Now, plugging these values back into molarity equation, M = moles/volume in liters = 0.011625 mol / 0.0075 L = 1.55 M.
So, the concentration of NaCl doesn't change, it stays the same. The answer is C) 1.55 M
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