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Answer :
Final answer:
To calculate the distance moved by an accelerating runner, apply the kinematic equation for motion with constant acceleration. Given an initial velocity of 1 m/s, acceleration of 2 m/s², and 3 seconds of time, the runner moves a total of 12 meters.
Explanation:
It is related to kinematics in physics and involves calculating the distance covered by a runner who accelerates over time. To solve for the distance the runner moved, we can use the kinematic equation which combines initial velocity (v_i), acceleration (a), and time (t):
Distance (d) = v_i × t + ½ × a × t²
Given the initial velocity of 1 m/s, acceleration of 2 m/s², and time of 3 seconds, the calculation would be:
d = 1 m/s × 3 s + ½ × 2 m/s² × (3 s)²
d = 3 m + ½ × 2 m/s² × 9 s²
d = 3 m + 9 m
d = 12 m
Therefore, the runner has moved 12 meters during the 3-second acceleration period.
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