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Answer :
Final answer:
The centripetal acceleration of Enceladus in its orbit around Saturn can be calculated by converting the given period into seconds and using the formula for centripetal acceleration with the given orbital radius.
Explanation:
The subject of your question pertains to the field of physics, specifically the area dealing with orbital mechanics and centripetal acceleration. To calculate the centripetal acceleration of Enceladus, we first need to convert the orbital period from days into seconds. Given Enceladus completes one (circular) orbit of Saturn in 1.37 days, and there are 24 hours in a day, 60 minutes in an hour, and 60 seconds in a minute, we find the orbital period is 1.37 days * 24 * 60 * 60 = 118,368 seconds.
With the radius of the orbit (r) being 2.38×10⁸m, we can calculate the centripetal acceleration (a) using the formula: a = 4π²r/T² where T is the period of the orbit in seconds. Substituting the given values, we get: a = 4π² * (2.38*10⁸ m) / (118,368 s)² which yields the centripetal acceleration.
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