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Answer :
Answer:
Step-by-step explanation:
Given that it is assumed that a set of test scores is normally distributed with a mean of 120 and a standard deviation of 10.
If X is set of test scores, then X is N(120,10)
We can convert any x score to z score and vice versa as
[tex]z=\frac{x-100}{10} \\x=10z+100[/tex]
a) P(X<100) =P(Z<0) =0.50=50%
b) P(X<120) = P(Z<2) = [tex]\frac{95}{2} =47.5%[/tex]
c) P(X<140) = P(Z<4) = 1
d) P(X<60) = P(Z<-4)=0
e) P(X<60) = 0
f) P(X>120)=P(Z>2) = [tex]\frac{100-95}{2} =25%[/tex]
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