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Three children are riding on the edge of a merry-go-round that is 122 kg, has a 1.60 m radius, and is spinning at 19.3 rpm. The children have masses of 22.4 kg, 29.5 kg, and 32.8 kg. If the child who has a mass of 29.5 kg moves to the center of the merry-go-round, what is the new angular velocity in rpm?

Approximate the merry-go-round as a solid disk, and each child as a point mass.

Answer :

Three children are riding on the edge of a merry-go-round that is 122 kg, has a 1.60 m radius, and is spinning at 19.3 rpm. the new angular velocity in rpm when the child moves to the center of the merry-go-round is 19.3 rpm, which remains unchanged.

To solve this problem, we can apply the principle of conservation of angular momentum. Initially, the total angular momentum of the system is given by:

L_initial = I_initial * ω_initial,

where I_initial is the moment of inertia of the merry-go-round and ω_initial is the initial angular velocity.

When the child with a mass of 29.5 kg moves to the center, the moment of inertia of the system changes, but the total angular momentum remains conserved:

L_initial = L_final.

Let's calculate the initial and final angular velocities using the given information:

Given:

Mass of the merry-go-round (merry) = 122 kg

Radius of the merry-go-round (r) = 1.60 m

Angular velocity of the merry-go-round (ω_initial) = 19.3 rpm

Mass of the child moving to the center (m_child) = 29.5 kg

We'll calculate the initial and final moments of inertia using the formulas:

I_initial = 0.5 * m * r^2, (for a solid disk)

I_final = I_merry + I_child,

where I_merry is the moment of inertia of the merry-go-round and I_child is the moment of inertia of the child.

Calculating the initial moment of inertia:

I_initial = 0.5 * m_merry * r^2

= 0.5 * 122 kg * (1.60 m)^2

= 195.2 kg·m^2.

Calculating the final moment of inertia:

I_final = I_merry + I_child

= 0.5 * m_merry * r^2 + m_child * 0^2

= 0.5 * 122 kg * (1.60 m)^2 + 29.5 kg * 0^2

= 195.2 kg·m^2.

Since the child is at the center, its moment of inertia is zero.

Since the total angular momentum is conserved, we have:

I_initial * ω_initial = I_final * ω_final.

Solving for ω_final:

ω_final = (I_initial * ω_initial) / I_final.

Substituting the values we calculated:

ω_final = (195.2 kg·m^2 * 19.3 rpm) / 195.2 kg·m^2

= 19.3 rpm.

Therefore, the new angular velocity in rpm when the child moves to the center of the merry-go-round is 19.3 rpm, which remains unchanged.

To know more about angular refer here:

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